(D^2-5D+6)=x^2-x+2

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Solution for (D^2-5D+6)=x^2-x+2 equation: 



(^2-5+6)=D^2-D+2

We move all terms to the left:

(^2-5+6)-(D^2-D+2)=0

We add all the numbers together, and all the variables

-(D^2-D+2)=0

We get rid of parentheses

-D^2+D-2=0

We add all the numbers together, and all the variables

-1D^2+D-2=0

a = -1; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·(-1)·(-2)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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